identify the 33rd term of the arthmetic sequence 9, 7 1/2, 6
\(\Large \color{purple}{\rightarrow 9{1 \over 2} - (n)({1 \over 2}) }\) Substitute n with 33.
the general formula for an arithmetic sequence is:\[a_n=a_1+d(n-1)\]
@amistre64 Yes, I just simplified the formula and added that 1/2 to 9.
they give you a1, they give you n=33 the only thing to do is figure out the common difference (d) between each term.
yes, but the real question stems from not knowing how to do these things in general.
answers -39 thanks for your help
the common difference can be determined simply by subtracting 2 terms that are side by side: a2-a1 is the simplest way to me: 7 1/2 - 9 = -1 1/2 \[a_{33}=9-\frac{3}{2}(33-1)\]
im trying to see how Parth got that setup :)
-39 is correct; but i cant get that with your setup ... is there a typo?
\(\Large \color{purple}{\rightarrow 9 - (n -1)({1 \over 2}) }\) \(\Large \color{purple}{\rightarrow 9 - {(n - 1) \over 2} }\) \(\Large \color{purple}{\rightarrow {18 - (n - 1) \over 2} }\) \(\Large \color{purple}{\rightarrow {18 - n + 1 \over 2} }\) \(\Large \color{purple}{\rightarrow {19 - n \over 2} }\) \(\Large \color{purple}{\rightarrow 9.5 - {n \over 2} }\) Simplified. @amistre64 Can I please please please have a medal?
I'm sorry about asking for the medal, but still am I right?
33/2 = 16.5 -16.5 9.5 ------ - 7.0 which is not= -39
the common difference is not -1/2, is where your error is creeping in at
See it Oh lol it's 3/2
other than that, your simplification would have been sufficient
\(\Large \color{purple}{\rightarrow 10.5 - {3n \over 2} }\)
\(\Large \color{purple}{\rightarrow 10.5 - 49.5 }\) \(\Large \color{purple}{\rightarrow -39 }\)
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