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Mathematics 17 Online
OpenStudy (anonymous):

A cubical box has a side-length of 1m. It is placed next to a wall which is perpendicular to the ground. A ladder 4.9 meters long is placed so that it rests against the ground, the and an edge of the box as shown in the diagram.

OpenStudy (anonymous):

Let xm and ym be the lengths of AB and AC respectively a. find BD in tems of x b. find CF in terms of y c. prove that /\ DBE is similar to /\ FEC. Hence show that xy=x+y d. prove that x2 + y2=24 e. use parts c and d to prove that (y+y)2 - 2(x+y)-24=0 f. at what height does the ladder rest against the wall? g. does f have more than one solution?

OpenStudy (pfenn1):

Okay. a. find BD in terms of x AD + BD = AB right?

OpenStudy (pfenn1):

Okay. We know what AD and AB are from what the problem gives us, right?

OpenStudy (pfenn1):

So write the equation for BD in terms of x?

OpenStudy (pfenn1):

yes

OpenStudy (pfenn1):

no, not necessarily....we don't know what BD is at this point. AB = AD + BD =1 + BD = xm rearrange and solve for BD BD=xm-1

OpenStudy (pfenn1):

would what be 7 meters?

OpenStudy (pfenn1):

I don't know how you are getting these numbers? Can you show me your work?

OpenStudy (pfenn1):

Oh. Yeah, I was a little thrown by that as well. I don't think we can use those boxes, because the box is 1 m but 9 of the little boxes, so what does that mean? So I am ignoring them for now.

OpenStudy (pfenn1):

a. they only seem to want the length of BD in terms of x so what is that?

OpenStudy (pfenn1):

I think you might be getting ahead of yourself. They just want you to find BD and CF in terms of x and y for now.

OpenStudy (pfenn1):

I showed you above that for a. BD = xm - 1, remember?

OpenStudy (pfenn1):

I don't know yet. The first question is Let xm and ym be the lengths of AB and AC respectively a. find BD in tems of x BD = xm - 1 the second question is b. find CF in terms of y Can you do this one?

OpenStudy (pfenn1):

I could. I have already shown you. AC = AF + CF =1 + CF = ym rearrange and solve for CF CF=ym-1

OpenStudy (anonymous):

I know there are comments from another person but can anyone explain it in a better way to where i can understand it easier?

OpenStudy (anonymous):

|dw:1336774065283:dw| so you have the expression for DB and FC, and FE=DE=1 put in the values and solve to prove xy=x+y

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