Some numbers can be expressed as the sum of a string of consecutive positive numbers. Which numbers have this property?
Is there more to the question? This question doesn't seem to be very well posed. (In other words, there are plenty of assumptions we need to make before answering it.)
All numbers but the power of 2.
I should add, all POWERS of 2.
i stilll dont understand
Try it out. 9 = 2+3+4 But say 16: 4+5+6 = 15, 5+6+7=18. You can't do it.
@finaiized , how do you go about proving this is true? :)
theres some examples but i dont understand how to do it 9 = 2 + 3 + 4 11 = 5 + 6 18 = 3 + 4 + 5 + 6
I'm not sure if this completely counts as proof, but the reason is that powers of 2 have no even factors other than 1. And two consecutive numbers (one of which must be odd) cannot be represent a power of 2.
@inthemoment666 What do you mean "How to do it?" Do you not understand the example? Or the answer?
so pretty much has to be an even number right?
@inthemoment666 -- Do you know what the phrase "powers of 2" means? For example, can you name the first four "powers of 2"? This is helpful for understanding the discussion. :)
Not an even (look at your example: 18. It has odd factors, like 9). Only numbers that aren't Power of 2.
@mathteacher1729 - Powers of 2 are in the form \(2^n\). The first four (excluding n=0) is 2, 4, 8, 16, 32.
@finaiized I was asking @inthemoment666 , not you. :-p
@mathteacher1729 - Aww derp. Didn't read :P
okay i think i get it?
@finaiized You also gave the first FIVE powers of two... where I had asked for the first FOUR. :-p
@inthemoment666 Can you name the first five powers of THREE? :) (understanding the phrase "powers of... a number" is important.
yeah i know what POWER means there 9 27 81 right?
Yep.
i feel dumb D':
(But @mathteacher1729 asked you for five... I just mentioned it because he burned me when I listed more than 4 :( )
i dont care i got it did i not
Yes. As to this question, I'm not sure if your teacher expects you to know this off the bat or what. But it's something you can remember I guess.
9 = 2 + 3 + 4 then what do i do with the problems
This is an interesting question in number theory which deals with divisibility. It requires lots of guessing and testing (and/or) a pretty sophisticated understanding of the factors and divisibility of numbers. Out of curiosity -- what class is this question from?
you want a hint? think of numbers that cannot be expressed as such a sum also note that as in your above example \(\frac{2+3+4}{3}=3\) i.e. \(9=3\times 3\) also try \(4+5+6+7=22\) and \(\frac{4+5+6+7}{4}=5.5\) the number half way between 5 and 6
meaning of course that \(22=11\times 2\) lets try another one \(6+7+8+9+10=40\) and \(\frac{6+7+8+9+10}{5}=8\) so \[40=8\times 5\]
so far we have \[9=3\times 3\] \[22=2\times 11\] \[40=8\times 5\] keep trying and you will notice something if you still need help let me know
@Numbers Hello!
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