Couple questions for Algebra 1 and up!!
A couple of questions i like the sound of that hahahah
\[6n^{-3}y/2n^{-1}y^{-3}\] haha yeah ive done these before but icant remember exactly...
oh, im suppoed to simplify that
oh gawd i hate those
To start - write it as a fraction like it should be. Then realize negative exponents mean it's 1 over the exponent.
just subtract your bottom exponents from your top exponents; then sort the madness
I did write it as a fraction, i couldnt find the button for that now. Like i said, my teacher was out today and over the year we did the charpters out of order... like 123456789 12 11 10, and my teacher was out so a sub gave us the wrong thing or something
get the reciprocal to remove the negatives because no polynomial can have a negative exponent. then simplify.
amistre i have no clue what u are talking about :/
the button is: type in, frac{}{} into the eq editor
subtraction; its the opposite of addition :/
\[\frac{n^{top}}{n^{bottom}}=n^{(top-bottom)}\]
\[\frac{6n^{-3}y}{2n^{-1}y{-3}}\]
thats y^{-3}
so, the number part is just a normal fraction 6/2 the rest is n^(-3--1) y^(1--3)
i know subtraction is the opposite of addition!!! i didnt know if you took away the bottom N when it simplified 6n/2n.:( i went to kindergarten :(
:) just subtract the bottom stuff from the top stuff (exponentwise); after you simplfy see if you still got negative exponents; if so, drop them under the bar
Let's start here: \[\frac{6n^{−3}y}{2n^{−1}y^{−3}}\] Personally I like writing negative exponents as a reciprocal first. The effect is moving it from bottom to top or top to bottom: \[\frac{6yn^{1}y^{3}}{2n^{3}}\] Then simplify: \[\frac{6n^{1}y^{4}}{2n^{3}}\] And subtract exponents as they are being divided \[\frac{3y^{4}}{n^{2}}\]
Thank you! and i have another one... what is the degree of the polynomial mean?
\[\frac{6n^{−3}y}{2n^{−1}y^{−3}}=3n^{(-3--1)}y^{(1--3)}\to\ 3n^{-2}y^4=\frac{3y^4}{n^2}{}\]
the degree of a poly is the highest exponential count of a single term
4xyz = degree 3 x^2 y^5 = degree 7 etc ..
but only variables count for some reason
And of course, terms are separated by + or -: \(4x^2y^5+4j^6-3x^2+5\) Can you find the degree of this polynomial?
single term as in \[2x^{3}y\] not \[2x^{3}y-4xy^{2}+9x^{3}y^{2}\]
right? and the degree is 7
Right and right.
so the degre of the one i posted is.. 5?
Yep, on the last term.
cool! one more, if you can? Which binomial is a factor of \[6x ^{2}+x+12\]? 3x-3,3x-4, 6x+3, or x+4
What do you wish to find?
Idk the question is Which binomail is a facot of that thing that i posted up ther^
You'll have to use the quadratic formula to factor this, unless you mean 6x^2+xMINUS 12, which I think you do.
i do yteah, soorry
Factor by decomposition. Find two numbers that multiply to 6*12 and add up to the coefficient of x, 1.
when i factored it, i got (3x+4)(2x-3). thats not any of theanswers
\[6x^2+x-12\] \[6x^2+9x-8x-12\] \[3x(2x+3)-4(2x+3)\] \[(3x-4)(2x+3)\]
yeah i saw what i did wrong thanks ! :)
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