Question

a grasshopper jumps off the ground with an initial vertical velocity of 4 feet per second. After how many seconds does he reach the ground? please use the vertical motion formula h=-16t^2+vt+s

Answer 1

OK ewrt. You'll have to remember the equation for projectile motion, which is the one you just gave. You'll have to substitute the value v=4ft/sec into that equation and let s=0 since the grasshopper started from the ground (initial height). So you'll get h=-16t^2+4t. Solve for h, then you'll get t=1/16 seconds. I believe that correct...tell me if I am wrong....I forgot a lot of physics. lol

Answer 2

Actually let h equal zero because the grasshopper ended up back on the ground. Thus, you'll have to let h=0 and solve for t. Hope that helps!

Answer 3

so 0=-16t^2+4t?

Answer 4

I believe that is correct. When you solve for t, you'll get the value t=1/16. Do you have the solution?