Question

uhmm since i got the volume thing done...time to ask...how do you find the work thingy using integral calculus??

Answer 1

uhmm maybe i should ask what the formula for work is...i know in physics it's work = force x distance...what about here?

Answer 2

do you know @dpaInc ??

Answer 3

Oh, work is basically the definite Integral so work is \[W=\int\limits_{a}^{b}f(x)dx\] Hope this helps!

Answer 4

Do you have a specific problem???

Answer 5

uhmm guess a problem will help...

A 360-lb gorilla climbs a tree to a height of 20 ft. Find the work done if the gorilla reaches the height in 10 seconds.

Answer 6

where do i start there? no idea o.O

Answer 7

Can you tell me if this is physics or calculus? so i have a better idea to look up in my book.

Answer 8

calculus haha =))

Answer 9

Oh fabulous, because I am terrible at physics...ok hold on real quick.

Answer 10

sure sure ^_^

Answer 11

Hmm, my Calculus book doesn't show me how to integrate a function with respect to time as well....bummer, I 'll have to look into my physics book now....lol.

Answer 12

uhmm what is the first thing to do in work problems anyway? i mean you gave an equation \(\Large W = \int_a^b f(x) dx\) but i dont see a function o.O

Answer 13

I'm trying to find a way to relate the problem to a situation we could use to help solve the problem. There are several work problems the Integral is used to solve such as lifting weights, dealing with Hooke's Law (spring constant), or lifting a cable to the top of a building. What do you think this problem would classify as?

Answer 14

If work is done lifting something then it will require using Force as defined by Newton's Second Law of motion as the product of its mass and acceleration. so work can be W=Fd. (Work=Force x distance). etc.

Answer 15

ugh so many formulas @_@

Answer 16

OK lg, I think I got the idea but not the solution. I can only cut the question in half without integration...lol. If you're interested, you can read on. lol:

Let the mass of the gorilla be 360 (so m=360). Let the acceleration due to gravity be (g=9.81). So F=mg, thus F=3531.6 be the force. Let the distance be 20 ft so (d=20 ft). Thus the equation will look something like this: W=Fd=3531.6(20)=70632 ft-lb. Since there's time in the question, we'll have to integrate with regards to time, which I do not know how.

Does the question come with a hint? If it does, that'll be extremely helpful.

Answer 17

well i got how you got the numbers but i guess im more lost than you when it comes to thinking of the next step :p i wish @satellite73 know...

Answer 18

Work=Fd and F=ma so Work=mad!!!!!

Answer 19

You want to find the volume? o_O

Answer 20

no....the work using integral calculus

Answer 21

eh if ya integratin with respect to a variable treat all other variable expressions as konstants

Answer 22

http://tutorial.math.lamar.edu/Classes/CalcI/Work.aspx

http://www.youtube.com/watch?v=2pbInn9PkHQ

Answer 23

but i dont even know how to start this @Redlinl and i dont like math vids @saifoo.khan they intimidate me =_=

Answer 24

someone somewhere did some differential equation to get W=fd so keep integrating and deriving and such

Answer 25

haha lol =)) tough job :))

Answer 26

A 360-lb gorilla climbs a tree to a height of 20 ft. Find the work done if the gorilla reaches the height in 10 seconds.

Work is independent of time in this case it is just 360 lb* 20 ft

But beware the unites. If you want in newtons convert lbs to kilos and ft to meters.

Answer 27

this is not a physics question...this is an integral calculus question

Answer 28

Physics and calculus are one in the same. You should get same answer using either one. And Someon derived work for you using calculus.

SHould be something like w= Integral of mass with respect to distance from a to b

Answer 29

yeah...i need to know how to solve it using integral calculus :/

Answer 30

Well assuming just work due to gravity. If they want kinetic work then the time comes into play

Answer 31

just says work done..

Answer 32

well \[\int\limits_{0}^{20} 360 dx \]

Answer 33

7200 both my integral and F*D

Answer 34

arent the limits supposed to be the distance i mean \(\large W = \int_0^{20} (360)(9.8)dx\)
since force is mass x acceleration?

Answer 35

although says here that 7200 is right

Answer 36

why is there no acceleration?

Answer 37

wrong for 2 reasons
Acceleration 9.8 is in metric not US or English idk what they call it :P

Second lbs is not a mass it is weight. It is the English/us equivlent of the Newton.

Answer 38

i see...lol these metric and us systems are confusing =))

Answer 39

thanks got that cleared :D