Question

(x^2-1/4x-1/8)/(x+1/4)
evaluate

Answer 1

Is this the equation?\[\left( x^2 -\frac1 4 x- \frac 18 \right)\over x+\frac 1 4\]

Answer 2

yes

Answer 3

I would find the LCD of the top first\[ x^2 -\frac1 4 x- \frac 18\]what would be the LCD?

Answer 4

It would be 8. so the expression would be\[x^2 -\frac1 4 x- \frac 18=\left( 8x^2-2x-1\over 8 \right)\]

Answer 5

that would be 8

Answer 6

Do the same for the expression\[x +\frac 1 4=\left( 4x+1 \over 4 \right)\]

Answer 7

Now you can write the original equation\[\left[ \left( x^2 -\frac1 4 x- \frac 18 \right)\over x+\frac 1 4 \right]=\left( 8x^2-2x-1 \over 8 \right)\left( 4 \over 4x+1 \right)=\]

Answer 8

Now factor \[8x^2-2x-1\] Hint: one of the factors will be 4x+1

Answer 9

ty..trying to work it out now.....hold on one sec, please

Answer 10

i got 2x-1

Answer 11

Okay, now put it all together\[\left( 8x^2-2x-1 \over 8 \right)\left( 4 \over 4x+1 \right)=\left( (2x-1)(4x+1) \over8 \right) \left( 4 \over 4x+1 \right)\] and simplify

Answer 12

Don't know if it's right, but medal for effort.

Answer 13

What did you get for the final simplified expression?

Answer 14

i keep gettt...ugh

Answer 15

i keep getting something tottally different

Answer 16

Well, if I did okay up to the point above, then the final expression should be \[\frac 1 2 (2x-1)=x-\frac 1 2\]

Answer 17

how did you get that???

Answer 18

From above\[\left( (2x-1)(4x+1) \over8 \right) \left( 4 \over 4x+1 \right)\]The 4x+1 term cancels and 4/8=1/2 so then\[=\frac 1 2 (2x-1)=x-\frac 1 2\]

Answer 19

Maybe someone else will check what I did and see if I made any mistakes....

Answer 20

i'm checking it by doing the step i missed

Answer 21

i got confused with the sign after you multiplied the recipricol of 4x+1/4

Answer 22

it should be 4/4x-1

Answer 23

thanks for staying with me until understood it!!!

Answer 24

I'm not sure which part you are saying should be 4/4x-1?