Question

i need help with dividing this problem:
(x^4+x^3-10x^2+22x-8)/(x^2-3x+4)

Answer 1

\[\frac{x^4+x^3-10x^2+22x-8}{x^2-3x+4}\]

Just typesetting it.

Answer 2

that is the correct problem...help...please :)

Answer 3

You can do long division or you factor the numerator.

Answer 4

could you show me how to factor the numerator? please

Answer 5

\[(4 - 3 x + x^2) (-2 + 4 x + x^2)
\]

Answer 6

Your fraction becomes
\[\frac{x^4+x^3-10 x^2+22
x-8}{x^2-3 x+4}=\frac {\left(x^2-3 x+4\right)
\left(x^2+4 x-2\right) }{x^2-3 x+4}
\]
What is the answer?

Answer 7

x^2+4x-2

Answer 8

thanks...you made that look so easy....i was over analyzing....

Answer 9

yw

Answer 10

will you chec to see if I got an answer correct?

Answer 11

please

Answer 12

(x^2+1/3x-2/9)/(x-1/3).....I got the answer of x-2/3 is that correct?

Answer 13

i need help grahing a function: p(x)= -(x+2)(x-1)(x-3)