Question

Exponential decay: a farmer in china discovers a mammal hide that contains 30% of its original c-14. find the age of the hide to the nearest year.

N=N(sub o)e^-kt
N(subo)= initial amount of C-14 (at time=o)
N=amount of C-14 at time t
t=time in years
k=0.0001

Answer 1

you are given everything you need to set up the equation right?

Answer 2

N=N(sub o)e^-kt
N(subo)= initial amount of C-14 (at time=o)
N=amount of C-14 at time t
t=time in years
k=0.0001

Answer 3

\(N=30\%=.3, k=.0001\) so your job is to solve
\[.3=e^{-.000t}\] for \(t\) which takes the following two steps.
write in equivalent logarithmic form as
\[\ln(.3)=-.000t\] and then divide both sides by \(-.0001\) to get
\[t=\frac{\ln(.3)}{-.0001}\] and the final step is to use a calculator to see what the heck this number is

Answer 4

thank yu.

Answer 5

yw