Question

if x=5root2 - root6 then 56-20root3/5root2+root6 in terms of x is

Answer 1

\[x=5\sqrt2-\sqrt6\]
\[56-\frac{20\sqrt3} {5\sqrt2}+\sqrt6\]
??

Answer 2

no that root 6 is with 5root2

Answer 3

\[(56-20\sqrt{3})x/44\]

Answer 4

any one have doubts in question

Answer 5

yeah i still dont get the question

Answer 6

i gave you the answer

Answer 7

if x=52√−6√

56−203√52√+6√ this we have to write in terms of x root6 is with 5root2

Answer 8

options x^3/44 x/44

Answer 9

x^3/44

Answer 10

becouse (56−20 √ 3)=x^2

Answer 11

x^3 ???

Answer 12

ok can u plzzzz give the steps to do it plzzzz

Answer 13

look my previous answer and add this comment and you get your answer

Answer 14

steps are:
multiply the denominator by conjugate, which is x
and rest is just operations

Answer 15

let me try it ......

Answer 16

numerator how to solve it plzzz

Answer 17

\[(56-20\sqrt{3})x/(50-6)=x ^{2}*x/44=x^{3}/44\]

Answer 18

x*x=(5root2 - root6)(5root2 - root6)=56-20sqrt3

Answer 19

how (56−203√)x become x^3

Answer 20

x*x=(5root2 - root6)(5root2 - root6)=56-20sqrt3

Answer 21

got it?

Answer 22

hey the numerator i got as 300root2 - 156root6

Answer 23

hmm...
(5root2 - root6)(5root2 - root6)=25*2-5sqrt12-5sqrt12+6=56-10sqrt12=56-20sqrt3

Answer 24

denominator is 44 i got it i want to knw about the numerator

Answer 25

step1 multiply by conjugate:
(56-20root3)(5root2-root6)/(5root2+root6)(5root2-root6)

step 2: notice that:
(5root2 - root6)(5root2 - root6)= 56-20sqrt3

step 3 substitute the step 2 expression in stpe 1 expretion:
(5root2 - root6) (5root2 - root6)5root2-root6)/(5root2+root6)(5root2-root6)

step 4 perform operation in denominator:
(5root2 - root6) (5root2 - root6)5root2-root6)/44

step 5 substitute (5root2 - root6) =x in step 4 expretion:
x^3/44

Answer 26

got it?

Answer 27

wait..

Answer 28

okkk thanzxxxx

Answer 29

the largest number that leaves reminder 7 abd 8 when divided by 3248 and 4175 respectively is??

Answer 30

can u solve this

Answer 31

sry got to go

Answer 32

ohh