Question

help plzz...

Answer 1

How do you write \(\cosh y\) in terms of \(e^y\)?

Answer 2

(e^y+e^-y)/2

Answer 3

@FoolForMath any ideas??

Answer 4

\[\sinθ=\frac{e^{iθ}−e^{−iθ}}{2} ,\qquad \cosθ=\frac{e^{iθ}+e{−iθ}}{2},\]
\[\sinhθ=\frac{e^θ−e^{-θ}}{2},\qquad\coshθ=\frac{e^θ+e^{-θ}}{2}.\]

Answer 5

I posted the problem on math.stackexchange, http://math.stackexchange.com/questions/143905/problem-on-complex-analysis#143908

Answer 6

thanks @Ishaan94

Answer 7

But we still need to solve it lol

Answer 8

too hard for me