Question

Find the sum:

Answer 1

\[\sum_{0}^{15}2(4/3)^n\]

Answer 2

well the common term comes out i.e 2 and what you are left with is a GP..

Answer 3

What?

Answer 4

sum of n terms of Gp = a(r^n -1)/(r-1)

Answer 5

a is first term and r is common ratio ..

Answer 6

I'm oconfused because of the n=0

Answer 7

anything to power 0 is 1 ..whats the big deal ?

Answer 8

it becomes 2(1 + 4/3 + (4/3)^2 .... )

Answer 9

if you consider 1 to be part of GP ,, n=16,,if not then n=15 and then you have to consider 1 separately..

Answer 10

Okay :D And so after I work that out I'll have the answer?

Answer 11

yes .. i guess so..

Answer 12

Okay, final question. Where did the 1/4 come from?

Answer 13

what ? it doesnt come anywhere..

Answer 14

? okay well thank you for your help :D

Answer 15

pleased to help ^_^