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Physics 13 Online
OpenStudy (anonymous):

the length of second pendulum is equal to?

OpenStudy (anonymous):

the length of second pendulum is equal to?

OpenStudy (anonymous):

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OpenStudy (vincent-lyon.fr):

1.00 metre. It was the way it was was first suggested in the 18th century that the new unit of length (1 metre) be defined. Then they changed it for 1,000,000th part of a quarter meridian.

OpenStudy (anonymous):

in these 1.0002m, 1.02m, 2m, 0.002m ???

OpenStudy (vincent-lyon.fr):

What is value of g in your problem?

OpenStudy (vincent-lyon.fr):

With standard acceleration g = 9,80665 m/s² it should be 0.9936 m

OpenStudy (anonymous):

ans should be these 1.0002m, 1.02m, 2m, 0.002m ???

OpenStudy (anonymous):

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OpenStudy (anonymous):

using the formula \[T=(2*3.14)*\sqrt{(l/g)}\] \[l=(g*T*T)/(4*3.14*3.14)\] using g=9.8 m/s*s T= 1s l=0.22820 metre

OpenStudy (vincent-lyon.fr):

@krishnakumar123 Your formula is correct. Although it is not stated in the question, what is called a 'second-pendulum' is actually a pendulum that takes one second for a half oscillation (going from one end to the other). This is why the 'second-pendulum' has a period T = 2 s.

OpenStudy (anonymous):

@Vincent-Lyon.Fr thanks for your clear explanation.............................

OpenStudy (vincent-lyon.fr):

Some more information here: http://en.wikipedia.org/wiki/Seconds_pendulum

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