the length of second pendulum is equal to?
the length of second pendulum is equal to?
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1.00 metre. It was the way it was was first suggested in the 18th century that the new unit of length (1 metre) be defined. Then they changed it for 1,000,000th part of a quarter meridian.
in these 1.0002m, 1.02m, 2m, 0.002m ???
What is value of g in your problem?
With standard acceleration g = 9,80665 m/s² it should be 0.9936 m
ans should be these 1.0002m, 1.02m, 2m, 0.002m ???
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using the formula \[T=(2*3.14)*\sqrt{(l/g)}\] \[l=(g*T*T)/(4*3.14*3.14)\] using g=9.8 m/s*s T= 1s l=0.22820 metre
@krishnakumar123 Your formula is correct. Although it is not stated in the question, what is called a 'second-pendulum' is actually a pendulum that takes one second for a half oscillation (going from one end to the other). This is why the 'second-pendulum' has a period T = 2 s.
@Vincent-Lyon.Fr thanks for your clear explanation.............................
Some more information here: http://en.wikipedia.org/wiki/Seconds_pendulum
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