Question

Evaluate integral of logx dx

Answer 1

\[
\int\log x\ dx=x\log x - x + C
\]
That's just one that I've had memorized for ages, don't remember how I originally derived it.

Answer 2

Oh. Integration by parts with g'=1. Not hard at all :)

Answer 3

what s the first step?

Answer 4

For integration by parts remember the formula is:
\[
\int fg'=fg-\int f'g
\]
Set \(f=\log x\) and \(g'=1\) and then it's pretty easy :)

Answer 5

ohh ok f= log x and g =x thank you sooo much ..