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the last equation is supposed to be f'(1)=
@amistre64
after learning the derivative rules; you never go back to the limit definition ...
i knoow, but that's what he wants! ;/
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then plug in the (1+h) into the function and algebra it out; its simple enough with that function
\[\lim\frac{5-2(1+h)-(5-2(1))}{(1+h)-1}\]
well we have \[f'(1)=\lim_{\Delta x \rightarrow 0}(f(1+\Delta x)-f(1))/\Delta x\] we have f(1+delta x)= 5-(2*(1+delta x)) =3-2*(delta x) & f(1)= 3 put these in above equation we have (3-2*(delta x)-3)/delta x delta x gets cancelled & we have -2 as answer..
yeeah, thanks. i got it :))
good luck ;)
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