Question

cube root of 56 x to the fourteenth power

Answer 1

the cube root can be combined with the exponent as a fraction
cube root of x to the fourteenth power can be written as
x^14/3

so
cube root of 56x^14
(56x)^14/3

Answer 2

\[\huge (\sqrt[3]{56x})^{14}\]
\[\huge (56x)^{\frac{14}{3}}\]
\[\huge (56)^{\frac{14}{3}}*(x)^{\frac{14}{3}}\]
\[\huge (28*2)^{\frac{14}{3}}*(x)^{\frac{14}{3}}\]
\[\huge (14*2*2)^{\frac{14}{3}}*\sqrt[3]{x^{14 }}\]
\[\huge (7*2^3 )^{\frac{14}{3}}*\sqrt[3]{x^{12}*x^2 }\]
\[\huge (7)^{\frac{14}{3}}*(2^3 )^{\frac{14}{3}}*\sqrt[3]{x^{12}} \sqrt[3]{x^2 }\]
\[\huge \sqrt[3]{7^{14}}*(2^{14}) *x^4 \sqrt[3]{x^2 }\]

Answer 3

Thank you so much!!!