m trying to figure out how long the water from a fountain stays in the air. The equation for the fountain is y=-16x^2+68.5x+0 (68.5 is velocity and 0 is starting height) I think that gives me x intercepts of (0,4.2812,0) Now how do i see how long it stays in the air?
so what does the variable x represent?
time?
I'm not sure. I cant figure out how to do this . It says to substiute the velocity of 68.5 and the starting height into this equation. y=-16x^2+vx+s. I also know that the height of the fountain reaches 560 feet. What am I missing
Starting height is 0(s)
you are missing what the variable they are using is actually measuring ...
y = position with respect to time; the variable they use represents the time that has passed.
if you know the x intercepts; then you know the time that the height of the water starts (0) and the time it hits the ground again (the other intercept)
hmm, It says to graph equation and get x intercepts rounding to 5 . I did that and got (0, 4.2812,0). Then it says ,"how long does this mean the water from your fountain will remain in the air." I don't get it. I'm sorry. so what do I do now to get that answer.
so , is it 4.3 seconds?
what does this mean: (0, 4.2812,0) ?
thats what the x intercepts are , I think
are there 3 x intercepts?
I used the online graphing tool and it gave me that answer
try using wolframalpha.com then ....
but yes, 0 is the time it starts, and 4.28 is the time it lands
"68.5 is velocity and 0 is starting height" are we projecting it at an angle or vertically upwards?
@amistre64 ok. Thanks for the help. I really appreciate it.
vertically upwards
ah ok sorry, i thought x meant horizontal displacement. seems you have it sorted
Thank you though for answering
good luck
thanks , I'll need it!
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