Question

could someone plase help me...
"write as single logarithm with coefficient of 1"... see attachment

Answer 1

the answer would be ln((2x+2y)/z)^2 by the rules of logarithms

Answer 2

actually the final answer is ln [(x+y)^2/2z]...i wanna know how to ge there... but thnks

Answer 3

well we need to use 3) first with the middle logarithm

Answer 4

ok, you were right. the 2 outside the ln becomes the exponent. and all the subtracted lns become the denominator of the new ln.

Answer 5

\[-\ln2 + 2\ln(x+y) - lnz = \ln(x+y)^2 - lnz -\ln2\]

Answer 6

no i have -In2(x+y)^2-lnz... what do do with th -?