Could someone explain load resistors to me? How does a resistor draw a load? On a similar note, why does the voltage not change across a single resistor, but there is a voltage drop across that same resistor if there is another one in series with it?
what is your question ? draw a figure .
|dw:1336779101665:dw| It's not a schoolwork problem, just an issue with my understanding. I am talking about in the case above, when you go through the node method, there is no voltage drop across that resistor [box] from the voltage source [circle.] |dw:1336779236408:dw| but in this picture, there would be a voltage drop across resistor one, due to the adding of another resistor. I don't really get why the second resistor causes a voltage drop. UNLESS...I just thought of this, perhaps it has something to do with the other part of my question. Which is load resistors. I am unsure how a resistor provides a "load" on a circuit. We kind of glazed over it in class and just got a bunch of equations so I can calculate them to my hearts content but I don't understand the physics behind it. |dw:1336779437679:dw| for example sometimes we have a load resistor to test a thevenin or norton circuit. Or causing a "pullup" effect in a mosfet circuit to pull the voltage up. I don't know how a resistor causes this pulling effect.
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