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OpenStudy (anonymous):
Multiply sqrt(-2) * sqrt(-16)
can someone please help me with this one.
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myininaya (myininaya):
\[\sqrt{-2}=i \sqrt{2}\]
\[\sqrt{-16}=i \sqrt{16}=i \cdot 4= 4i\]
myininaya (myininaya):
Now multiply
myininaya (myininaya):
@eigenschmeigen a and b >=0 in order for that to be true
OpenStudy (anonymous):
good point. i thought something fishy was going on when i wrote that..
myininaya (myininaya):
\[i \sqrt{2} \times 4 i\]
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OpenStudy (anonymous):
so is i√2*4i the final answer?
OpenStudy (anonymous):
remember i x i = -1
OpenStudy (anonymous):
so -1*4i
myininaya (myininaya):
don't forget your sqrt(2) part
myininaya (myininaya):
and that extra i shouldn't be there
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OpenStudy (anonymous):
so after the i√2*4i what do i put. can you do step by step and explain to me from start to finish
OpenStudy (anonymous):
\[i \sqrt{2} \times 4i = i \times i \times \sqrt{2} \times 4 = -1 \times 4\sqrt{2} = -4\sqrt{2}\]
myininaya (myininaya):
\[i \cdot \sqrt{2} \cdot 4 \cdot i =i \cdot i \cdot 4 \cdot \sqrt{2} \text{ b/c multiplication is communative }\]
myininaya (myininaya):
lol oops i'm too late
OpenStudy (anonymous):
hehe i was speedy
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OpenStudy (anonymous):
you guys are great. It has been a long time for me
OpenStudy (anonymous):
so now can you tell me how you got all this i am kind of lost
myininaya (myininaya):
\[\sqrt{-1}=i\]
OpenStudy (anonymous):
ok so what is the final answer for the whole problem ?
by the way i like your pic, thats cute how do i put something on mine
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