how do you find the intercept of the equation 19x + y = 0
you rewrite the equation in slope-intercept form, y=mx+b. in this case, it is y = -19x. you can now input y=o to get the x-intercepts and x=0 to get the y-intercepts.
okay thanks, oh and how would you find the slope of this equation?
m is the slope since we're using slope-intercept form
so in this case the slope would be -19?
you are correct, the slope is -19
ok cool..thanks
okay how would you determine the angle of intersection for the lines: 4x-y+2=0 and 19x+y=0
i know you would have to find the slope of both equations which i did but i'm getting \[\theta=17 when \it should be \theta=163\]
notice how 17+163 = 180, so you're just calculating the supplement to the actual angle that you want
ohhh thats what i didn't do..thanks once again
you're welcome
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