how do you find the intercept of the equation 19x + y = 0
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OpenStudy (auctoratrox):
you rewrite the equation in slope-intercept form, y=mx+b. in this case, it is y = -19x. you can now input y=o to get the x-intercepts and x=0 to get the y-intercepts.
OpenStudy (anonymous):
okay thanks, oh and how would you find the slope of this equation?
OpenStudy (auctoratrox):
m is the slope since we're using slope-intercept form
OpenStudy (anonymous):
so in this case the slope would be -19?
jimthompson5910 (jim_thompson5910):
you are correct, the slope is -19
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OpenStudy (anonymous):
ok cool..thanks
OpenStudy (anonymous):
okay how would you determine the angle of intersection for the lines:
4x-y+2=0 and 19x+y=0
OpenStudy (anonymous):
i know you would have to find the slope of both equations which i did but i'm getting \[\theta=17 when \it should be \theta=163\]
jimthompson5910 (jim_thompson5910):
notice how 17+163 = 180, so you're just calculating the supplement to the actual angle that you want
OpenStudy (anonymous):
ohhh thats what i didn't do..thanks once again
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