Question

A soccer ball kicked on a level field has an initial
vertical velocity component of 15.0 meters per
second. Assuming the ball lands at the same
height from which it was kicked, what is the total
time the ball is in the air? [Neglect friction.]

Answer 1

I'm assuming the ball was kicked straight up in the air? If my memory servers me right, dividing by 9.8m/s^2 (gravity) should give you the time it was rising, double that to get falling time, so something in the nature of 3.1 seconds I would say. It has been 3 years since I took physics in high school so hopefully someone more reliable can answer this for sure.

Answer 2

Since the ball was kicked in air Vertically
Therefore: the gravitational Acceleration=-9.8 m/s^2
& V=0 m/s Where U=15.0 m/s
Since: V=U+GT
therefore:0=15.0-9.8T ,So, T=15/9.8=1.53 Sec
Since:the ball took the same distance up & down So the time is = Too
therefore:Total (T)=1.53X2=3.06 Sec Appro.

Answer 3

Thank you for the better explination, I rounded to 3.1s but I also got 3.06s to be exact.

Answer 4

JopHP, what does U and GT stand for?

Answer 5

U: is the initial Velocity
while GT: is the gravitational Acceleration X Time
law of motion
v=u+at

Answer 6

\[t=(2u \sin \theta)/(g)\]

t=(2*15)/(9.8) because the vertical velocity component is u sin theta.

t=3.061 seconds