Prove that: ((Sin x)^2 + 2 Cos X -1)/((Sin X)^2 + 3Cos X -3) = ((Cos X)^2 + Cos X)/-(Sin X)^2
sometimes it helps to have sin x = y/r and cos x =x/r IDK might help
do you know how can you writing 1 like relation of sin^2 x and cos^2 x ?
Yes Sin^2 X
do you know this formula sin^2(x) +cos^2(x) =1
Yes but there's only so much you can do with that formula
so how do you think (sin x)^2 not equal sin^2(x) ?
thats the same expression written differently
yes right so than check it in your exercise please what you will can rewriting there if you know thie what i have wrote there now
if you know this what ...
\[(\sin ^{2} \theta+ 2\cos \theta -1)/(\sin ^{2} \theta + 3\cos \theta -3) = (\cos ^{2} \theta+\cos \theta)/-\sin ^{2}\theta\]
and ... ? so there you not have used thie relation of sin^2(x) +cos^2(x) in place of 1 ,why ?
this relation of ---
I'm having trouble understand what you're trying to say
so if you know that 1=sin^2(x) +cos^2(x) so than why you not write inside your equation in place of 1 this sin^2(x)+cos^2(x) ? - so if you will write this there will can seeing what will get inside parantheses
come on i like make you understanding all this proof because will be very easy
little help (sin^2(x) +2cos x -1) so if there you write 1=sin^2(x)+cos^2(x) than what will get ? sin^2(x) +2cos x -((sin^2(x) +cos^2(x))) = sin^2(x) +2cos x -sin^2(x)-cos^2(x) = =2cos x -cos^2(x) - so yes ?
so in denominator there is 3cos x -3 - what can you factorizing out ? and what will get hence ?
can you understanding this all or ... difficile ?
Oui je comprends
c'est bien mon amie - so if i have wrote it right ,correct ?
bon,nous pouvons continue ,je pense ,oui ?
ou apré cette moment tu peux continue seulment ?
J'ai 1-Cos2^(X) + 3(Cos X -1) pour le denominateur
sorry i think my farnche not is correct because i have learned it in my schooles in 1987 was the last year
oh this sign that you have understood it all my words correct sure ?
Yeah I used the trig identities
ok nice thank you for this courage for franche language so firstly check it please in numerator what will remaining there ?
(2 Cos X - Cos^2 X)/(Sin^2 X + 3(Cos -1))
yes and now make this what i have maked in numerator write 1 in function of sin and cos - but inside parantheses you missed one x
je m'apelle André et tu ?
ok we make different steps - look if you know that 1=sin^2(x) +cos^2(x) what can you writing in denominator sin^2(x)= ... ?
- so for you can understanding more easy we need rewriting all terms of sin(x) in function of cos(x)
yeah Sin^2(X) becomes 1-Cos2^x
yes than so what will get in denominator ?
1- Cos2^X + 3(Cos X -1)
I meant 1- Cos^2 X + 3(Cos X -1)
yes right but this sign of exponent you not write in correct place
oh y
ok
and now can you rewriting all this exercise just using cos x so without sin x ?
sorry but my internet conection with server is very very slowly
You can rewrite all Sin^2 X with 1- Cos^2 X but the Cos X is the problem
not is problem you need rwriting your exercise just without sin x ok ?
how will be ?
so you dont like tel me what is your really name ?
1- Cos2^X + 3(Cos X -1) this is the denominator
it becomes (2 Cos X - Cos^2 X)/(1- Cos2^X + 3(Cos X -1))
what we know that 2cos(x) -cos^2(x) cos^2(x) +cos(x) --------------------- = --------------- 1-cos^2(x) +3(cosx -1) (-(1-cos^2(x))) - yes ?
2cos(x) -cos^2(x) cos^2(x) +cos(x) --------------------- = --------------- 1-cos^2(x) +3(cosx -1) (cos^2(x)-1)
yes is correct - so but now how do you like your exercise ,is more easy look because there are just cos of x ,yes ? - and in this case how do you think what can we make for solving this equation ?
The question here is to prove one side is equal to the other side, I don't think solving for Cos of X is neccessary
ok is right but for you can makeing the calcules more easy you need note the cosx =y - ok ?
so than what will get ,how will be your exercise ?
2y-y^2 ------------- = 1-y^2 +3(y-1) -can you continue ?
y^2 +y = -------- y^2 -1 can you continue ?
come on we will ending imediatly !!!
right side becomes y/(y-1)
so there are 2y-y^2 y^2 +y -------------- = ------- 1-y^2 +3(y-1) y^2 -1 yes you are right ,so the left parte ?
I see how it goes
can you calcule till the end please ?
y(2-y) -------------- (y-1)(2-y)
left side = right side
ok correct and now you wann tel what is your really name and was my pleasure that i have helped to you in this nice proof hope so much that is ,that was understandably sure
My name is Wulusi, Thanks!
thank you and you are really franche ?
I studied in Quebec
in Canada ,ok and your birth country is Canada too ?
Yeah I'm Canadian
thank you so my wife ask me what is the clock there now ?
2:22 am
so the proof was understandably ?
yeah I understand it
2:22 am what sign that there is saturday too like here in Budapest ,country Hungary but here is now 8:24
ahhh good morning!
thank you and for you sweet dreams so if you will sleep after this now
yeah thank you too!
pardon for my question but you have not name like Robert,or Michel or ... , or this name Wulusi is the same name or this is your family name ?
Yeah that is my name, my parents are From China
ok was my pleasure good luck bye aurevoir - so if this is correct ?
and do you know my country ? or the capital city Budapest ? - here are so much people from China too - and you are girl or boy ?
Hungary? I'm a boy
ok thank s ,yes Hungary ,in midle of Europe
and on what class you learn now ?
I'm just doing this math question to help my friend, I'm in biotechnology
ok and hence how many years ,how old are you please ? i am 43
and my hobby is math i dont learn now
just i like help people - so if i can
I'm 23 I'm not really good at math haha
ok thank s have a nice day and good luck byebye
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