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Solve: \[\frac{2x}{x+1} = \frac{2x-1}{x}\]
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Cross - multiply.
2x(x)=(2x-1)(x+1)
and x cannot be -1 or 0 :)
uhmm okay...
\(\Large \color{purple}{\rightarrow 2x(x) = (2x - 1)(x + 1) }\)
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Do you know igba, why we cross multiply?
so \[2x62 = 2x^2 + x - 1\]
that's \(2x^2\)
that right?
yes
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\(\Large \color{purple}{\rightarrow 2x^2 = 2x(x + 1) - 1(x + 1) }\) \(\Large \color{purple}{\rightarrow 2x^2 = 2x^2 + 2x - x - 1 }\) \(\Large \color{purple}{\rightarrow 2x^2 = 2x^2 + x - 1 }\)
yay so what's next @Diyadiya
\(\Large \color{purple}{\rightarrow 0 = x - 1 }\) \(\Large \color{purple}{\rightarrow x = 1 }\)
Note how I subtracted \(2x^2\) from both sides.
got it ?
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i think so..ill try more problems thanks :)
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