Question

two bodies seperated by a distance of s start moving towards each other with speeds of v and 2v respectively the uniform acceleration with which the first body should move so that they meet at the middle?

Answer 1

the answer is 8v^2/s

Answer 2

let the time in which the particles in the middle as t
then
2v*t=s/2
or t=s/4v

now for 2nd particle we have
s/2=v*t+1/2*a*t^2 where a is the required acceleration
or s=2vt+a*t^2
we know that 2vt=s/2
hence
a*t^2=s/2
put the value of t=s/4v here

we get a=8V^2/2s

Answer 3

2v*t=s/2 did nt understand

Answer 4

the velocity of a particle is given as 2v which is constant throughout
hence 2v*t=s/2 this particle moves with constant velocity to reach in the middle to cover up a distance of s/2..(velocity*time=distance)

Answer 5

ok

Answer 6

thanzz

Answer 7

here time is the key which is same for both the particles.. both the particles require the same time to reach in the middle..