a stone is dropped into a well from the open mouth of the well the water level is at a depth of 25m the sound of splash is heard after 2.31s from its release the speed of stone in air inside the well is (g=10m/s^2)

Question

a stone is dropped into a well from the open mouth of the well the water level is at a depth of 25m  the sound of splash is heard after 2.31s from its release the speed of stone in air inside the well is (g=10m/s^2)

anonymous · Answer

I didn't really get it..You want the velocity of the stone just before it hits the water?And if so why do we need both time and depth, only one of them would be fine.

anonymous · Answer

we have to find the speed of stone.... the answer is 357m/s

anonymous · Answer

OK. we have to find the speed of the stone, but we also have to give some more details.When you say, the speed of the stone inside the well someone would suppose that you mean just before it hits the water, an other one though could assume that you mean the velocity of the stone  1s after released, unless you clarify what you want.

anonymous · Answer

I think about it this way:
we don't know the initial speed of the stone. So for solving the problem the time that took for the stone to reach the water is: T = 2,31- (25/343,2), where 343,2 is the speed of sound in the air.
The rest is commun problem

anonymous · Answer

@shameer1

anonymous · Answer

Oh yes, now it makes sense, sorry guys i don't know if it is due to the lack of punctuation or due to my own exhaustion but i didn't see we had to use the speed of sound in the air.I am sorry for the mix up.

anonymous · Answer

it should be an easy one just find out the time in which stone will reach bottom.. minus it from 2.31
which will give u the time in which sound reaches your air...
now divide the depth of well by this time which gives u the velocity of sound in air

anonymous · Answer

thanxxx