Question

find the number of 2*2 matrix satisfying...
i) aij is 1 or -1
ii) (a11)2 +(a12)2 = (a21)2 + (a22)2 =2
iii) a11a21 + a12a22 =0

Answer 1

sounds like a symmetric matrix.

Answer 2

umm...yea...symmitric or skew symmitric

Answer 3

i think that's it. Not sure though/

Answer 4

yea...i think 16 such matrices cn be there as each place cn hv 2 occupantz...hence it shud be 2*2*2*2

Answer 5

itz a mayb..

Answer 6

Questions: Why are you doing these puzzle problems? Is it for HW?

Answer 7

assignment....self practice...

Answer 8

Doesn't seem useful in my opinion....Idk it's something I know my prof will never ask me for. The only puzzle problem I was asked in my class was one where I had to use cramers rule.

Answer 9

ver r u frm??

Answer 10

me?

Answer 11

umm..no romero

Answer 12

vese me amritsar se hu n u?/

Answer 13

chandigarh

Answer 14

California

Answer 15

o ohkeyy..m frn india...nd i thnk my teachrz require every typ of such topicz...:(

Answer 16

Every teaches differently. It's understandable. I know my prof focuses more on theorems and proofs than anything else.

Answer 17

mmm...yeahh...teachrz put alot in pressure here....sooo..any guesses fr solution??

Answer 18

2(a11)+(a12)=2 .../2
a11+a12=1
a11=1-a12
a11=1 Or -1from the question. and same for a12. but .
1=1-a12 only when a12=0 ,and -1=1-a12 when a12=2 right . (didn't match the 1st condition)
so i don't think there is really any matrix that satisfy those conditions you mentioned.
still maybe i am wrong idk.

Answer 19

umm sry..i typed wrong..i meant (a11)^2 +(a12)^2 = (a21)^2 + (a22)^2 =2..
..they were square!!