What is the slope of the line passing through the point (4, -3) and perpendicular to the line y = 2x + 1? Write your answer as a fraction.
The slope of a perpendicular line will always be the negative reciprocal of the slope of the line given. Since the line given has a slope of 2, you want a slope of \[-1\over 2\]
Next, do you know the point-slope formula? I'm not sure what you mean "write your answer as a fraction."
y-y1=m(x-x1) Does that look familiar? Just do some algebraic manipulation to get the answer you want.
thank you
but there is only one point , so how would yo use the formula y-y1=m(x-x1) ?
You have one point yes, but notice how in the line you gave you have an x and a y? (y=2x+1)
Same situation, the x and y remain as variables. The x1 and y1 come from the point given.
so it would be 1- (-3)= -1/2 ( 2-4)
actually no
You're looking for a formula right? That means that you NEED n x and a y. Otherwise you just have a number, not the equation of a line. An equation of a line will always be y=mx+b. Which is slope-intercept form.
yea so you only need the (4, -3) to find the slope of the line
No, the slope of the line is - (1/2) Your line can take three forms: standard, point slope, or y-intercept. For our purposes, you have enough information for point-slope. (notice how it's point not points)
so it would be y-(-3)= (-1/2)(x-4)
BINGO. Now, you just need to do algebraic manipulation to get the answer you want since I don't really know what you mean by writing the answer as a fraction.
but how would you solve it? because it would be y+3= (-1/2) (x-4) Solve for Y & X separately
Well, I don't know what you mean by "Write your answer as a fraction." That's the only issue.
\[y+3={-{\frac 1 2}} \times (x-4)\] You can distribute the -(1/2) and subtract 3 from both sides to get your answer in point-slope form. \[y+3={-{\frac 1 2}}x+2\] \[y={-{\frac 1 2}}x-1\]
I guess you could get a common denominator of 2.
so it would be -1/2 because it is asking for the slope right?
Pardon?
You said you wanted the answer as a fraction, not the slope. The slope will obviously be a fraction.
Never mind...extra information
the question asked what is the slope of the line
Right, sorry. I thought it wanted an equation. In that case, as I said earlier, an equation of a line has three forms. For a question like this, you want to first change it into point-slope form.
oops, I mean y-intercept.
In this case, you already have it in y-intercept form. The point given (4,-3) is extra information.
You have a slope of 2 so \[\huge any\] line with a slope of -1/2 will be perpendicular to the line given.
That extra point is only if you're looking for a \[\large specific\] line. My mistake sorry.
Can I at least get a medal or do I not get one because I read the question incorrectly and basically wasted your time by going in circles? :)
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