Question

Integrate

e^((-3x+2sinx)/6)

Answer 1

Check it here.
http://www.wolframalpha.com/input/?i=int+%7Be%5E%28%28-3x%2B2sin+x%29%2F6%29dx

Answer 2

Let u = -3x+2sinx)/6
du/dx = ...

Answer 3

I have written the formula but my explored break down xD
First use integration by parts, integrate, derivate e^xblabla expresion and integrate 1. Then you will have another integrate in which you could do a substitution using the e exponent.

Answer 4

Int ( e^u) = e^u/ du

Answer 5

Still not sure about this - any help?

Answer 6

correct your problem.

Answer 7

\[\exp((-3x+sinx)/6)\]

Answer 8

\[\exp((-3x+2sinx)/6)\]

Answer 9

that what I mean, sorry

Answer 10

I need to integrate it. I have made some progress but need to check it

Answer 11

it has no solution i think it was e^-3x (sinx/6)

Answer 12

i have got
-2 e ^(sinx/6) -(x/2)

Answer 13

Can anybody tell if this seems correct?

Answer 14

no i certainly tell you that your problem has a mistake

Answer 15

Ok. How?

Answer 16

You need a range limits of integration

Answer 17

sinx can not be in power of e^