from the top of a tower of height 20m a boy drops one stone ,one second later he throws another stone vertically downwards so that both hit the ground together the initial velocity of the second stone is (g=10m/s^2)
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OpenStudy (ajprincess):
try this and tell me if you find any difficulties
OpenStudy (anonymous):
i tried this but i got different answer so i posted this question...... all the question which i am posting is already tried by me ......
OpenStudy (ajprincess):
ohh k.
OpenStudy (ajprincess):
let me guide u
OpenStudy (anonymous):
thats a good idea....
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OpenStudy (anonymous):
i think first we have to find time???
OpenStudy (ajprincess):
nw first give me the answer?
OpenStudy (anonymous):
15m/s
OpenStudy (ajprincess):
As usual use s=ut+1/2at^2
OpenStudy (anonymous):
we have to find t is it....
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OpenStudy (ajprincess):
ya u r right.
OpenStudy (anonymous):
t=2s
OpenStudy (ajprincess):
this one u worked out nw or the given answer?
OpenStudy (anonymous):
next what to do t1=t2
OpenStudy (ajprincess):
the times wont be equal.
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OpenStudy (ajprincess):
t1=t2-1
OpenStudy (anonymous):
yes u r right
OpenStudy (ajprincess):
for jst dropping the initial velocty is 0.
OpenStudy (anonymous):
ok
OpenStudy (ajprincess):
so u cn find t1 using that adn t2 too.
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