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Mathematics 20 Online
OpenStudy (anonymous):

PLEASE HELP!!!!! If f(x) = (1/3)x - 4, find (f^(-1))(-3).

Parth (parthkohli):

You'd multiply (-1) by 1/3 and then multiply the result with -3.

Parth (parthkohli):

You'd multiply 1/3 then subtract 4 *

OpenStudy (anonymous):

Yes, I'm a bit confused.

OpenStudy (australopithecus):

oh lol yeah

OpenStudy (australopithecus):

thats much easier

Parth (parthkohli):

Oh wait, yes, didn't see that.

OpenStudy (anonymous):

That's okay, don't worry about it! @Australopithecus

OpenStudy (australopithecus):

f(x) = (1/3)x - 4 in this case set y to x and x to y and solve for y x = (1/3)y - 4 = 0 = (1/3)y - 4 - x = -(1/3)y = - 4 - x = y = -3(- 4 - x) f^(-1)(-3) = -3(-4 - (-3))

OpenStudy (australopithecus):

there that is the answer

OpenStudy (australopithecus):

i switch the variables just to make it easier to follow

OpenStudy (anonymous):

Wow! Thank you SO much! I really do appreciate it! Thank you, as well, to everyone else who helped!

OpenStudy (australopithecus):

now i need to pass out I cant believe i didnt notice it was an inverse function

OpenStudy (anonymous):

Sorry - what do you mean? Are you saying that you did the steps incorrectly?

OpenStudy (australopithecus):

no I did it correctly the negative exponent on the function means it is an inverse function

OpenStudy (anonymous):

OH, okay. That's good :)

OpenStudy (australopithecus):

which means that it is a graph were the y becomes the x and the x becomes the y

OpenStudy (australopithecus):

you can only do this on functions that are 1 to 1, that is pass the horizontal line test

OpenStudy (australopithecus):

since what you are graphing in linear and passes the test thus you can determine its inverse, some functions such as trigonometric functions we need to restrict the domain to determine the inverse.

OpenStudy (anonymous):

Okay.

OpenStudy (australopithecus):

for example sin(x) the graph is |dw:1336840694759:dw| If we were to flip this graph sin(x) we would get something like this |dw:1336840746017:dw| which doesn't pass the vertical line test, which means that if you draw a line vertically through a graph and it passes the line of the graph more than once then you do not have a function thus we restrict its domain from [-pi/2,pi/2] so that it is a function |dw:1336841002801:dw| now it passes the vertical line test and the thus the horizontal line test

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