Question

The area of a rectangle is 20 cm² after its dimensions were doubled. What is the area of the original parallelogram?

Answer 1

OldArea=height*length
after dimensions doubled:
NewArea = 2height*2length=4(height*length)=4(OldArea)

Answer 2

I am not 100% sure but I think it might be 1/4 of the area it got now.
First the area was a * b. Now it is 2a * 2b = 4 a * b. So earlier it only got a quarter of the area it got now after the doubling process.

Answer 3

o ya, sry. Missed that you had are after the doubling.... not befor

Answer 4

I guess this is only true if you got 90 degree angles - if you got a parallelogram I think this does not apply because the hight of the thing does change in a different way if you double the sides.

Answer 5

@TomLikesPhysics is right

Answer 6

but with this information you can't say for sure, becouse we have no angle....

Answer 7

so the answer is 90 angle ?

Answer 8

At begining says "The area of a rectangle", later it becomes "area of the original parallelogram"

Answer 9

so i guess it0s a rectangle

Answer 10

If you got 90 degree angles the area before was 1/4 of the area it got now. If you do not have a 90 degree angle I think the answer would need some sine or cosine and would be way more complicated.

Answer 11

so the answer is square?

Answer 12

the answer is a quarter of the area it got now

Answer 13

so how would u write that in number form

Answer 14

Area now = 4 * Area earlier or A(new)=4*Area(old)

Answer 15

A(new)=20cm^2 so A(old)=5cm^2