Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Find a counterexample for the statement: For all x ≥ 2, 3x ≤ x2.

OpenStudy (anonymous):

Its =2. ;)

OpenStudy (anonymous):

2 ≥ 2 is true, but 3 • 2 ≤ 2^2 is false.

OpenStudy (anonymous):

Preston concludes that, because the quadrilateral shown has congruent diagonals that bisect each other, it must be a rectangle. What type of reasoning is he using?

OpenStudy (anonymous):

Hold on ill brb to answer your question :).

OpenStudy (anonymous):

Sorry took so long im back now. :): The answer is he is using Geometric reasoning.

OpenStudy (anonymous):

3x<=x^2 x^2-3x>=0 x*(x-3)>=0 x<=0 or x>=3 now x>=2 thus x>=3

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!