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Find a counterexample for the statement: For all x ≥ 2, 3x ≤ x2.
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Its =2. ;)
2 ≥ 2 is true, but 3 • 2 ≤ 2^2 is false.
Preston concludes that, because the quadrilateral shown has congruent diagonals that bisect each other, it must be a rectangle. What type of reasoning is he using?
Hold on ill brb to answer your question :).
Sorry took so long im back now. :): The answer is he is using Geometric reasoning.
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3x<=x^2 x^2-3x>=0 x*(x-3)>=0 x<=0 or x>=3 now x>=2 thus x>=3
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