Mathematics
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OpenStudy (anonymous):
4x^25? this is the last question
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Parth (parthkohli):
Do you mean \((4x)^{25}\)?
OpenStudy (anonymous):
no i meant 4x^2-25
jimthompson5910 (jim_thompson5910):
4x^2-25
(2x)^2-25
(2x)^2-5^2
(2x-5)(2x+5)
So 4x^2-25 completely factors to (2x-5)(2x+5)
OpenStudy (anonymous):
oh haha that was easy thanks so much :)
jimthompson5910 (jim_thompson5910):
you're welcome
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OpenStudy (anonymous):
wait one more lol x^2-1
jimthompson5910 (jim_thompson5910):
x^2-1
x^2-1^2
(x-1)(x+1)
Parth (parthkohli):
\(\Large \color{purple}{\rightarrow x^2 - 1^2 }\)
\(\Large \color{purple}{\rightarrow (x + 1)(x - 1) }\)
jimthompson5910 (jim_thompson5910):
So x^2-1 completely factors to (x-1)(x+1)
OpenStudy (anonymous):
you just square both of them
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jimthompson5910 (jim_thompson5910):
Yes you write each term as a square (if possible)
Parth (parthkohli):
Yes, in these cases.
jimthompson5910 (jim_thompson5910):
Then you use the difference of squares factoring rule
OpenStudy (anonymous):
ok thanks
Parth (parthkohli):
Yes, and that rule says:
\(\Large \color{purple}{\rightarrow a^2 - b^2 = (a + b)*(a - b) }\)
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OpenStudy (anonymous):
is there any other answer..bc i dnt have that answer lol
jimthompson5910 (jim_thompson5910):
which answer choices do you have?
OpenStudy (anonymous):
never mind i got it haha...i have to do this by tonight..finals