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Mathematics 12 Online
OpenStudy (anonymous):

4x^25? this is the last question

Parth (parthkohli):

Do you mean \((4x)^{25}\)?

OpenStudy (anonymous):

no i meant 4x^2-25

jimthompson5910 (jim_thompson5910):

4x^2-25 (2x)^2-25 (2x)^2-5^2 (2x-5)(2x+5) So 4x^2-25 completely factors to (2x-5)(2x+5)

OpenStudy (anonymous):

oh haha that was easy thanks so much :)

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

wait one more lol x^2-1

jimthompson5910 (jim_thompson5910):

x^2-1 x^2-1^2 (x-1)(x+1)

Parth (parthkohli):

\(\Large \color{purple}{\rightarrow x^2 - 1^2 }\) \(\Large \color{purple}{\rightarrow (x + 1)(x - 1) }\)

jimthompson5910 (jim_thompson5910):

So x^2-1 completely factors to (x-1)(x+1)

OpenStudy (anonymous):

you just square both of them

jimthompson5910 (jim_thompson5910):

Yes you write each term as a square (if possible)

Parth (parthkohli):

Yes, in these cases.

jimthompson5910 (jim_thompson5910):

Then you use the difference of squares factoring rule

OpenStudy (anonymous):

ok thanks

Parth (parthkohli):

Yes, and that rule says: \(\Large \color{purple}{\rightarrow a^2 - b^2 = (a + b)*(a - b) }\)

OpenStudy (anonymous):

is there any other answer..bc i dnt have that answer lol

jimthompson5910 (jim_thompson5910):

which answer choices do you have?

OpenStudy (anonymous):

never mind i got it haha...i have to do this by tonight..finals

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