The loudness of a sound in decibels is related to the intensity of the sound i, where the function for the loudness is given by L(i)=101og10(i/i0), and io is a constant equal to the minimum sound that can be detected by the human ear. a. Find the loudness in decibels of a rock music recording with an intensity of 10 million times io.
\[L(i)=10\log_{10}(\frac{i}{i_0})\]and you are told to find loudness of music that has:\[i=10,000,000*i_0=10^7*i_0\]so you get:\[L(i)=10\log_{10}(\frac{10^7*i_0}{i_0})\]the \(i_0\)'s cancel and you should then be able to calculate the loudness.
So it would come out to be L(i)=10log10(10^7)?
Then I calculate?
yes, and you should be able to simplify the log
\[\log_{10}(10^a)=a\]
therefore:\[\log_{10}(10^7)=?\]
yes 7, but you didn't need wolfram for that, I showed you the rule above ^^^
so now you should be able to calculate the value for loudness
Oh woops :/ Yea, thank you! a refers to the 7.
yes :)
So would the answer be 7 million?
no....
\[L(i)=10\log_{10}(\frac{10^7*i_0}{i_0})=10\log_{10}(10^7)=10*7=?\]
I meant 70 million. But nvm. 10*7=70
yes, answer is 70 (not 70 million)
Oh o.k. Thank you so much for your help asnaseer!
yw - I'm glad I was able to help :)
Would you happen to understand this question? c.In terms of decibels, how close is the intensity level of the rock music recording to the threshold of pain?
I think you'll need to google that. try and search for how many decibels a human ear can stand before it becomes painful. for rock music I guess the loudness is 70 decibels from the equation above.
O.k cool. Thanks!
IIRC the threshold of pain for the human ear is 120dB, but you might wanna check that
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