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Find the zeros f(x)=(x+3)^2(x-5)^6 and state the multiplicity
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If you don´t have a "+" between (x+3)^2 and (x-5)^6 then the ceros are in front of your nose. Because it is a big product, if one term of the product becomes cero, then all the product ´ll be cero. See that if x + 3 = 0 then all ´ll be cero, and the same for x - 5 = 0, all will be cero. Then could see that x = -3 and x = 5 (solving) are the ceros.
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