Evaluate the integral. Express your answer using words or symbols. (-2sinx)dx....find the antiderivative
-2*cos(x)
\[\int -2 \sin x dx\] simply take the -2 out of the integral then integrate sin x
You can test it by taking the derivative of whatever you got. To solve this problem, you need to think backwards. What do you take the derivative of in order to get -2sinx? Well, if you think about it, the derivative of cosx = -sinx. If you want to get -2sinx, the antiderivative would be 2cosx. Remember, you could test this by taking the derivative of it. The derivative of 2cosx = -2sinx.
oooh... wow, thanks you guys! :)
You're welcome! ^_^
ooh it actually 2 cos x not -2 cos x :P
sinnce integral of sin x is - cos x and you can put the constant outside of the integral operator -2 int(sinx dx) = 2 cos x Fixed
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