Question

How do I solve this?

Let f(x) = x-6 and g(x) = x^2-x+4. Find g(f(x)).

Answer 1

Im confused with Order of Operations..

Answer 2

sub f(x) into g(x)

Answer 3

plug in x-6 into every x in x^2-x+4

Answer 4

Think that f(x), once you valuated X, F(x) es another number. Then, you use that number and evaluate it in G.

Answer 5

g(f(x))means replace every x in the function g with the f(x)

Answer 6

Order of Operations, it can become

(x-6)^2 or x-(6)^2 or x(-6)^2

Answer 7

plug in x-6 into every x in x^2-x+4

Answer 8

( x-6)^2-( x-6)+4

Answer 9

think of x as a place holder for x-6 use perenthesis they are your friends

Answer 10

so then it is
(x-6)^2-x+6+4?

Answer 11

Right?

Answer 12

Yes.

Answer 13

yes

Answer 14

x^2+36-x+10
x^2-x+46?

Answer 15

That cant be right...

Answer 16

x^2-13*x+46