Question

a boat moves from p to q (downstream) in 2.5 h and from q to p (upstream) in 5 h respectively when the engie is producing maximum speed on the boat in each case . if due to increased water flow the speed of flow of the river gets doubled how long will it take the boat(moving with possible speed) to move from

(a) p to q (downstream) (b) q to p (upstream)

Answer 1

the answer is (a) 2h (b) 10h can anybody give me the steps plz...

Answer 2

Downstream
\[L=Vr.t=(Vmax+vriver).t\]
Upstream
\[L=V'r.t'=(Vmax-vriver).t'\]

Answer 3

ok

Answer 4

solve it and then put v river times two

Answer 5

what????

Answer 6

he said the vriver has doubled

Answer 7

can u give the eq plzz

Answer 8

ok wait

Answer 9

vmax = 3s/10

Answer 10

is that answer correct...

Answer 11

\[vmax=3.vriver\]

Answer 12

oh....no

Answer 13

after finding v max should we find speer of river???

Answer 14

\[L=(Vmax+vriver).2,5=(3.vriver+vriver).2.5=4.vriver.2.5\]

Answer 15

Now we doubled v river
\[L=(Vmax+2.vriver).t=(3.vriver+2vriver).t=4.vriver.2.5\]
so t= 2h

Answer 16

no idea !!

Answer 17

what you dont get?

Answer 18

L=(Vmax+2.vriver).t=(3.vriver+2vriver).t=4.vriver.2.5 ???????????

Answer 19

here we find L as a function of vriver
\[L=(Vmax+vriver).2,5=(3.vriver+vriver).2.5=4.vriver.2.5\]

Answer 20

plzz help ????

Answer 21

i 'll take a picture for you

Answer 22

ok