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Mathematics 14 Online
OpenStudy (anonymous):

the displacement of a particle moving along a straight line at time t is given by x=1+ 2t +3t^2 the instantaneous acceleration is?

OpenStudy (anonymous):

65

OpenStudy (anonymous):

the ans = -5 units

OpenStudy (anonymous):

Sorry hit 6 by mistake

OpenStudy (radar):

x is displacement: 3t^2+2t+1 x' is velocity : 6t + 2 x'' is acceleration: 6 a constant. I guess I am doing this wrong.

OpenStudy (anonymous):

we need instantaneous acceleration

OpenStudy (anonymous):

the ans = -5 units

OpenStudy (radar):

It appears that acceleration is a constant 6, so the instaneous acceleration would be 6. Where am I going wrong here, the approved answer is -5........how is that possible.

OpenStudy (radar):

I am giving up on this one shameer1

OpenStudy (anonymous):

sorry the ans=6 units

OpenStudy (anonymous):

sorry for typing mistake

OpenStudy (radar):

So 6 it is. great.

OpenStudy (anonymous):

plzz help new http://openstudy.com/study#/updates/4faf233ce4b059b524fa3a64

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