z sports car moving on a straight road at speed of 288km/h...the air brakes are applied till the speed reaches 144km/h ,producing a uniform deceleration of 10m/s^2...at 144km/h speed the regular brakes are applied till car stoppedproducing a uniform deceleration of 5m/s^2 the distance travelled by the car from the instant of applying the air brakes till it stopped is

Question

anonymous · Answer

sorry it is not z ti is (the)

stormfire1 · Answer

You need to simply break this problem into parts.  
Determine how long it takes for the car to brake from 288 km/h to 144km/h.  Then calculate the distance travelled during that period.

Do the same thing for the next part...then just add up the distances.  I'm too lazy to do it at the moment :)

anonymous · Answer

use $$v^2=u^2+2as$$ and find s for both cases. the distance travelled is the addition of 2 of the s.