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Mathematics 11 Online
OpenStudy (anonymous):

The electric field due to a uniformly charged sphere is maximum at :

OpenStudy (anonymous):

outer surface..i guess

OpenStudy (anonymous):

u guess?

OpenStudy (anonymous):

see electric field is indirectly proportional to the square of distance..and at the centre its zero..so id say ki hona to surface pr hi chahiyen..but lemme confirm again

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

see this question is a bit incomplete..as the E falls 1/r^2..the maximum strength would lie either inside the sphere or on the surface..it would depend upon the range given to you for the value of R

OpenStudy (anonymous):

there r 4 options centre of sphere inside the surface at the surface at infinite distance from the centre

OpenStudy (anonymous):

go for inside the surface..the lesser distance the better

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

once you move out of the sphere the sphere behaves like a point charge.- E=k*q/r2-so r=R at the surface maximum field strength... but if r->infinity then E=0.think so...

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