Question

Evaluate.
7!/4!3!

1
35
210

Answer 1

\[\Large \color{purple}{\rightarrow {7 * 6 * 5 * 4 * 3 * 2 * 1 \over 4 * 3^2 * 2^2 * 1 } }\]

Answer 2

no need to expand... just use 7! = 7*6*5*4! and cancel out the 4!

Answer 3

Cancel the terms that exist in both numerator and denominator.

Answer 4

I was explaining it in the most basic way.

Answer 5

\[\frac{7!}{4!3!} = \frac{7\times 6\times 5\times 4!}{4!3!}=\frac{7\times 6\times 5}{3 \times 2 \times 1}\]\[=7 \times 5 =?\]

Answer 6

35

Answer 7

Yup :)