Question

solve:
ln x - ln(x-1)=1

Answer 1

log(a) - log(b) = log(a/b)

use this log property

Answer 2

We have
\[\ln x -\ln (x-1)=1\]
Do you know the properties of logarithm? How it's defined?

Answer 3

i have it to \[\ln (x/x-1)=1\]

Answer 4

Now take antilogarithm both sides. Do you know how to do that?

Answer 5

not ringing a bell currently

Answer 6

Ok
\[\ln x=y\]

\[=>x=e^y\]
Do you understand this?

Answer 7

yes

Answer 8

SO here we have
\[\ln\frac{x}{x-1}=1\]
Taking antilog
\[\frac{x}{x-1}=e^1\]
\[\frac{x}{x-1}=2.782\]
I think you can find x now, Can't you?