Question

\[\large \int \frac{1}{\sqrt{1 - t^4}}dt\]

Answer 1

initial guess...
t = sqrt(sin u)

Answer 2

That makes dt=.5cos u/sqrt(sin u), which might be a bit of a pain... but that was my initial guess too.

Answer 3

for the record...i do not know how to solve this...

Answer 4

Oh, 1-t^4=(1-t^2)(1+t^2), so just do t=sin u

Answer 5

It will still be awkward though because of the 1+t^2 part. And if you do t=tan u then the 1-t^2 part will be awkward. hmmmm

Answer 6

suppose t@2 is= u

Answer 7

that gives
\[\frac{1}{2}\int\limits_{?}^{?}\frac{1}{\sqrt{u} \sqrt{1-u^{2}}} du\]

Answer 8

you can all give up now...
http://www.wolframalpha.com/input/?i=integrate+1%2Fsqrt%281-t^4%29+dt

hmm elliptical integrals

Answer 9

Haha thank you for checking that, I would have been working on this for another 15-30 minutes :P

Answer 10

courtesy of @apoorvk lol

Answer 11

Lol @lgbasallote