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If g(x) = 3x + 5, what is g–1(x)? a. (x-5)/ 3 b. (x+5)/3 c. (x+3)/5 d. (x - 3) /5 Confused... help....
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It'd be the inverse of g(x). Do you know about inverses?
im not sure... in fraction?
See, the inverse of adding is subtracting. The inverse of multiplying is dividing.
ok.. what is the inverse of g(x)?
You'd subtract 5 and divide by 3.
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I would say A because if you solve for x you will get [g(x) - 5]/3 = x. Switching the g(x) with the x will give you the inverse: g^-1(x) = (x-5)/3
divide what by three?
Exactly. The inverse is: (x - 5)/3
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