When simplifying the expression 2/x + 2/(x-1) + 2/(x+2) the denominator is x(x+1)(x–1). What is the numerator? a. 6x2 + 8x + 4 b. 6x2 + 4x – 4 c. 6x2 + 9x + 4 d. 6x2 + 9x – 4
Shouldn't the denominator be x(x-1)(x+2) ?
i thought that too...
so what do u think?
The second choice (b) would be the answer if the denominator is x(x-1)(x+2). But I can't get any of the choices if the denominator is what you stated.
but that is what the problem say not me... i dont konw what to think now...
I dunno. The least common denominator of the fractions is x(x-1)(x+2). I don't think there's a way to change that to x(x-1)(x+1). I'm thinking it's a typo.
so this can being the common denominator just in case if you rewrite the denominator of 3rd term in (x+1) so hence will be the 3rd term 2/(x+1)
i dont get it...
what and how where ?
i dont get waht u said... i mean i try to do this problem and the demoinator isnt x(x+1)(x–1), so i dont no what to dowith the top
,,sar12" can you rewriting here now correct your exercise ,how is in your math booke ?
what? u first have to find the common demoninator which is supposed to me x(x-1)(x+2)
yes now this is right but how you have wrote in your exercise that is x(x-1)(x+1) so this not can being right common denominator ok ?
i get that but the question says that is the denominator.....
so i think that this is very difficile understanding for me --- sorry
thats fine...
so you need understanding that if there are fractions with denominators a,b and c so than the common denominator not can being never a*b*d - hope this is understandably right sure now for you ok ?
there is a typo here, that is all.
ok great... then what should i do.. are the answers correct?
the denominator must be the product of the denominators. it cannot be anything else
so even the options are wrong?
well lets check...
numerator is \(6x^2+4x-4\)
how?
Yes, all the options are wrong if you use the denominator given,
Because to convert from the denominator you would expect to see, to the denominator you are given, you need to multiply the numerator by (x+1)/(x+2), and the numerator does not divide completely by x+2, so none of the options can be correct.
(because none of them have remainders). It is a typo.
so it is option 2 when you add fractions you have to take the product of the denominator. you do not have any other choice if there are variables in the denominator and no common factors clearly there are no common factors in \(x\), \(x-1\) and \(x+2\)
ok so its b, i got it now... but the denominator is wrong... :)
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