can you help me with this for my exercises:

I need to to show that:
g(x)= (e(-3x+2sinx)/6)
----------------
(3+2cosx)

has derivative

g'(x)= - (4(sin^2)x -12sin x +5) (e(-3x+2sinx)/6)
-----------------------------------
6(3+2cosx)^2

Question

can you help me with this for my exercises:

I need to to show that:
g(x)= (e(-3x+2sinx)/6)
           ----------------
                (3+2cosx)

has derivative

g'(x)= - (4(sin^2)x -12sin x +5) (e(-3x+2sinx)/6) 
              -----------------------------------
                                    6(3+2cosx)^2

aravindg · Answer

quotient rule !!

anonymous · Answer

http://www.wolframalpha.com/input/?i=derivative+of+g%28x%29%3D+%28e%28-3x%2B2sinx%29%2F6%29%2F%283%2B2cosx%29

anonymous · Answer

$$
g(x)=\frac{e^{\frac
   {1}{6} (2 \sin (x)-3
   x)}}{\cos (x)+3}\
g'(x)=\frac{e^{\frac{1}{6} (2 \sin
   (x)-3 x)} \left(6 \sin
   (x)+2 \cos ^2(x)+3 \cos
   (x)-9\right)}{6 (\cos
   (x)+3)^2}
$$

anonymous · Answer

$$
g'(x)=\frac{e^{\frac{1}{6} (2 \sin
   (x)-3 x)} \left(-2 \sin
   ^2(x)+6 \sin (x)+3 \cos
   (x)-7\right)}{6 (\cos
   (x)+3)^2}
$$

anonymous · Answer

It seems to me that your g'(x) is not 100% right.