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Mathematics 14 Online
OpenStudy (anonymous):

how to factor 8x^3+10x^2+12x+15 by grouping

OpenStudy (anonymous):

1. what is the GCF of 28 and 16?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

correct. what is the GCF of x^2 and x?

OpenStudy (anonymous):

x

OpenStudy (anonymous):

correct. so pull out 4x from both terms as follows: 4x(?+?)

OpenStudy (anonymous):

4x(7x+4)

OpenStudy (anonymous):

correct.

OpenStudy (anonymous):

2. What is the GCF of 8, 10, 12 and 15?

OpenStudy (anonymous):

1

OpenStudy (anonymous):

correct so that doesn't help. some of these questions require certain groupings to find what the question is looking for.

OpenStudy (anonymous):

wouldn't you group 8x^3+12x and 10x^2+15

OpenStudy (anonymous):

So 8x^3 and 10 x^2 have GCF of 2x^2. SO pull that out and put it in this form: 2x^2(?+?)

OpenStudy (anonymous):

yes you could do it the way I was doing it or the way you are doing it. To arrive at the simplest factorization, it is sometimes trial and error

OpenStudy (anonymous):

8 and 12 gfc would be 4 and 10 and 15 gfc is 5

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

4x(x^2+3)+ 5(2x+3)

OpenStudy (anonymous):

almost--4x(2x^2+3)+5(2x^2+3) ok?

OpenStudy (anonymous):

4x(2x^2+3)+5(2x^2+3)

OpenStudy (anonymous):

how to simplify it to get an equation in the forms of (x+-?)(x+-?)

OpenStudy (anonymous):

sorry, I got up to get some water. still there?

OpenStudy (anonymous):

look at the expression as if it had two parts --one part to the left of the + sign before the 5 and the other part to the right side of it. Well both sides have a common factor-- (2x^2+3). S factor that out to get (2x^2+3)(4x+5)

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