find the area of the triangle whose sides have the given lengths.
a=1, b=2, c=2

Question

find the area of the triangle whose sides have the given lengths. 
a=1, b=2, c=2

amistre64 · Answer

use herons formula, or find an angle with the law of cosine

anonymous · Answer

@ Chiomatn use the method i gave you it is valid for all

anonymous · Answer

is s=2.5?

anonymous · Answer

@Chiomatn93 , I just told you the answer few minutes back.  The heron's formula

amistre64 · Answer

|dw:1336932257283:dw|

c^2 = a^2 + b^2 -2ab cos(C)

c^2-a^2-b^2
------------ = cos(C)
     -2ab

             c^2-a^2-b^2
cos^-1 (------------) = C
                    -2ab

2^2 sinC
-------- = area 
    2

anonymous · Answer

that wasnt the answer... u just gave me the formula

anonymous · Answer

@Chiomatn93 ,  I am not here to give answers :(

anonymous · Answer

If you want some help , I can help you

anonymous · Answer

all i want is the steps and answer.. i already know the formula.. is s=2.5?

anonymous · Answer

yes

anonymous · Answer

@ chiomatn93 be confident in what you are you would make mistakes I also did just keep on trying

anonymous · Answer

@Chiomatn93, you need a calculator, not us :P

anonymous · Answer

Let
$$s =\frac {a+b+c}{2}=\frac 5 2\
Area= \sqrt{ s(s-a)(s-b)(s-c)}=\frac {\sqrt{15}}{4}
$$

amistre64 · Answer

if never been fond of the heron formula :)

anonymous · Answer

im getting decimals

anonymous · Answer

$$
\frac{\sqrt{15}}{4}\approx 0.968246
$$